0=-200x^2+1600x-2320

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Solution for 0=-200x^2+1600x-2320 equation:



0=-200x^2+1600x-2320
We move all terms to the left:
0-(-200x^2+1600x-2320)=0
We add all the numbers together, and all the variables
-(-200x^2+1600x-2320)=0
We get rid of parentheses
200x^2-1600x+2320=0
a = 200; b = -1600; c = +2320;
Δ = b2-4ac
Δ = -16002-4·200·2320
Δ = 704000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{704000}=\sqrt{6400*110}=\sqrt{6400}*\sqrt{110}=80\sqrt{110}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1600)-80\sqrt{110}}{2*200}=\frac{1600-80\sqrt{110}}{400} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1600)+80\sqrt{110}}{2*200}=\frac{1600+80\sqrt{110}}{400} $

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